In this paper, solution of the following difference equation is examined xn+1=xn−131+xn−1xn−3xn−5xn−7xn−9xn−11,{x_{n + 1}} = {{{x_{n - 13}}} \over {1 + {x_{n - 1}}{x_{n - 3}}{x_{n - 5}}{x_{n - 7}}{x_{n - 9}}{x_{n - 11}}}}, where the initial conditions are positive real numbers.