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Mean square calculus and random linear fractional differential equations: Theory and applications

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Figure 1

Approximations of the mean (left) and the standard deviation (rigth) of the solution SP to the random IVP (2)α = 0.7 and λ = 3/4 using different orders of truncations M = 6, 7, 8, 9, 10 over the time interval [0, 5].
Approximations of the mean (left) and the standard deviation (rigth) of the solution SP to the random IVP (2)α = 0.7 and λ = 3/4 using different orders of truncations M = 6, 7, 8, 9, 10 over the time interval [0, 5].

Figure 2

Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with α = 0.7 and λ = 5/4 using different orders of truncations M = 10, 12, 14, 16, 18 over the time interval [0,5].
Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with α = 0.7 and λ = 5/4 using different orders of truncations M = 10, 12, 14, 16, 18 over the time interval [0,5].

Figure 3

Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with α = 0.7, λ = 5/4, E[b0]=E[c]=−1 $\mathbb{E}[b_0]=\mathbb{E}[c]=-1$  and V[b0]=V[c]=1/4 $\mathbb{V}[b_0]=\mathbb{V}[c]=1/4$  using different orders of truncations M over the time intervals [0,5].
Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with α = 0.7, λ = 5/4, E[b0]=E[c]=−1 $\mathbb{E}[b_0]=\mathbb{E}[c]=-1$ and V[b0]=V[c]=1/4 $\mathbb{V}[b_0]=\mathbb{V}[c]=1/4$ using different orders of truncations M over the time intervals [0,5].

Figure 4

Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with M = 20, λ = 5/4, E[b0]=E[c]=−1 $\mathbb{E}[b_0]=\mathbb{E}[c]=-1$  and V[b0]=V[c]=1/4 $\mathbb{V}[b_0]=\mathbb{V}[c]=1/4$  using different orders of the derivative α = {0.4, 0.5, 0.6, 0.7, 0.99} over the time interval [0, 5].
Approximations of the mean (left) and the standard deviation (right) of the solution SP to the random IVP (2) with M = 20, λ = 5/4, E[b0]=E[c]=−1 $\mathbb{E}[b_0]=\mathbb{E}[c]=-1$ and V[b0]=V[c]=1/4 $\mathbb{V}[b_0]=\mathbb{V}[c]=1/4$ using different orders of the derivative α = {0.4, 0.5, 0.6, 0.7, 0.99} over the time interval [0, 5].
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Life Sciences, other, Mathematics, Applied Mathematics, General Mathematics, Physics